Patrick B. answered 04/28/20
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Math and computer tutor/teacher
(1/3)( 8x + 3y)^(-2/3) (8 + 3y') = 2x
8+3y' = 6x(8x + 3y)^(2/3)
3y' = 6x(8x + 3y)^(2/3) - 8
y' = (1/3)[6x(8x + 3y)^(2/3) - 8]
= [2x(8x+3y)^(2/3) - 8/3]