Please awnser all questions

Question

Consider the following distribution of data from a college survey.

	Android Users	iPhone Users	Total
Ages 18 – 30	405	653	1058
Ages 31 – 40	687	538	1225
Ages 41 – 50	1068	391	1459
Total	2160	1582	3742

(Write all answers as a percentage without the % symbol to 1 decimal.)

What is the probability that someone chosen at random was aged 41 - 50?

 

What is the probability that someone chosen at random was an Android user or aged 41 - 50?

 

What is the probability of someone being aged 41 - 50 and an Android user?

 

Given a random person was aged 18 - 30, what is the probability that they were an iPhone user?

Answer 1

P(41-50) = 1459/3742 = 0.39

P(Android or 41-50) = (2160 + 1459 - 1068)/3742 = 0.68

P(Android and 41-50) = 1068/3742 = 0.29

P(IPhone|18-30) = 653/1058 = 0.62