I think you will get your answer by long division.
1/(1-x3) = 1 + x3 + x9 + ...
and the interval of convergence is |x|<1
Yumi A.
asked 04/24/20Find a power series representation for the function; find the interval of convergence. (Give your power series representation centered at x = 0.)
f(x)= x/(1-x^3)
sum from n=0 to infinity [?] provided |x| < [?]
I think you will get your answer by long division.
1/(1-x3) = 1 + x3 + x9 + ...
and the interval of convergence is |x|<1
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