
Yefim S. answered 04/27/20
Math Tutor with Experience
Let take function 8/(1-8x) we can considered as sum of infinite geometric series with a1 = 8 and r = 8x.
Then 8/(1 - 8x) = 8 + 82x + 83x^2 + ... + 8^(n + 1)x^n + ... = ∑0∞8n + 1xn; Now we integrate both sides from 0 to x; ∫0x8/(1 - 8x)dx = ∑0∞∫0x8n+1)xndx; or - ln(1 - 8x) = ∑0∞8n + 1xn + 1/(n + 1); from here
f(x) = ln(1 - 8x) = - ∑0∞8n + 1xn + 1/(n + 1);
Interval of convergence we get from condition - 1 < r < 1: - 1< 8x < 1; from here - 1/8 < x < 1/8 ,
x ∈ (-1/8, 1/8)