Inactive Tutor answered • 04/22/20
Tutor
New to Wyzant
f(x) = (x + 3)(x - 2) 3
d/dx [f(x)] = (x-2)3 + (x+3)(3)(x-2)2 = 0
x = -1.75
Local Minimum = (-1.75, -65.918)
There is no local maximum
Calculus - local maximum and minimum
f(x) = (x + 3)(x - 2) 3 find the value(s) of x for which f has a local maximum and minimum
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