
Mark M. answered 04/20/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
2 = e7t\k
ln 2 = 7k
0.693 ≈ 7k
0.099 ≈ k
3 = e0.099t
ln 3 = 0.099t
1.099 ≈ 0.099t
11.097 ≈ t
Mark M. answered 04/20/20
Mathematics Teacher - NCLB Highly Qualified
2 = e7t\k
ln 2 = 7k
0.693 ≈ 7k
0.099 ≈ k
3 = e0.099t
ln 3 = 0.099t
1.099 ≈ 0.099t
11.097 ≈ t
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