f(x) = x - 2sinx f'(x) = 1 -2cosx
Setting slope = f'(x) = 0, we obtain x = cos-1(1/2) = π, 5π/6 (+ 2nπ for integral n)
Angie A.
asked 04/19/20For what values of x does the graph of f have a horizontal tangent? (Use n as your integer variable. Enter your answers as a comma separated
list.)
f(x)=x-2sin(x)
f(x) = x - 2sinx f'(x) = 1 -2cosx
Setting slope = f'(x) = 0, we obtain x = cos-1(1/2) = π, 5π/6 (+ 2nπ for integral n)
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