
Rini C. answered 04/16/20
Math made easy
f(x) = 4x+7/x
f '(x) = 4-7/x2
Solving f '(x) =0 we get x= -1.32, 1.32 and x=0 the function is undefined.
A= -1.32, B =0 , C = 1.32
Checking signs of f'(x) in the three intervals we find f(x) is inc in (−∞,A), dec in (A,B) and (B,C) , inc again (C,∞)
f ''(x) = 14/x3 which is never zero.
but sign of f''(x)<0 from (−∞,B), hence concave down.
f"(X) >0 in (B, ∞) hence concave up