
Nehemiah C.
asked 04/16/20infinite series
find he sum of the series of it converges else show that it diverges
∞
∑((1/n^2+7n+12)+((2^2n+1)/(5^n))
n->∞
1 Expert Answer
Richard P. answered 04/16/20
PhD in Physics with 10+ years tutoring experience in STEM subjects
I am a bit worried about precedence of operations issues in you question. Also, you do not make it clear whether the sum starts at n = 0 or n =1
So I will address the case that n starts at n = 0 and the required sum is the sum of two terms:
The first one (A) is
A = Σn=0 ∞ 1 /( n2 + 7 n + 12) and the second one (B) is B = Σn=0∞ 22n+1 / 5n
For A, the expression 1/(n2 + 7n +12) can be rewritten as 1/(n+3) - 1/(n+4) . By writing out the first few terms it can be seen that this is a telescoping series.
A = 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 +1/6 and so on. Thus A = 1/3
For B, the expression 22n+1 / 5n = 2 4n / 5n = 2 (4/5)n This is a geometric series with the common ratio = 4/5
So B = 2 /(1- (4/5) ) = 10
A + B = 10 + 1/3
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Bobosharif S.
Clarify the following: (1/n^2+7n+12) or (1/(n^2+7n+12)) and 2^2n+1 or(2^(2n+1)04/16/20