taking a derivative :)thanks in advance

Question

Take a derivative of (x^2+3x^3)/3x^2

Answer 1

f(x) = (x² + 3x³)/3x² = 1/3 + x ; f'(x) = 0 + 1 = 1;

Answer: f'(x) = 1

Answer 2

Hello Zoey! Before we find the derivative, simply divide each term in the numerator by the term in the denominator.

(x^2+3x^3) / 3x^2 ⇒ 1/3 + x

Derivative of a number is 0, and the derivative of x is just 1.

Therefore, d/dx( 1/3 + x ) = 0 + 1 = 1 >>>>>>>>>>>>>>>>> (ANSWER)

Hope this helps! Let me know in the comments for additional information.