f(1)=f(-1)=0
f' ≠ 0 anywhere
f is continuous at 0 but not differentiable at 0
Rolle's theorem does not apply
Bob M.
asked 04/13/20Consider the following function.
f(x) = 1 − x2/3
Find f(−1) and f(1).
f(−1) | = | ||
f(1) | = |
Find all values c in (−1, 1) such that f '(c) = 0.
(Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.)
c =
Based off of this information, what conclusions can be made about Rolle's Theorem?
This contradicts Rolle's Theorem, since f is differentiable, f(−1) = f(1), and f '(c) = 0 exists, but c is not in (−1,
This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−1, 1).
This contradicts Rolle's Theorem, since f(−1) = f(1), there should exist a number c in (−1, 1) such that f '(c) = 0.
This does not contradict Rolle's Theorem, since f '(0) does not exist, and so f is not differentiable on (−1, 1).
Nothing can be concluded.
f(1)=f(-1)=0
f' ≠ 0 anywhere
f is continuous at 0 but not differentiable at 0
Rolle's theorem does not apply
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