whats the equation?

Question

Write the equation of a line that is perpendicular to y=−x−6 and that passes through the point (−9,−4)left parenthesis, minus, 9, comma, minus, 4, right parenthesis.

Answer 1

we have y=-x-6

The given line is in slope intercept foam y= m*x + c

Where slope m= -1

Then slope of required line = -1/m = 1 (given that the required line is perpendicular to y=-x-6 )

And the given point is (-9,-4)

Now we have required to put these value in the point slope foam of line

which is ( y - y ₁) = m( x - x ₁)

y - (-4) = 1 *(x - (-9))

y = x + 5 (This is the required equation of line )

Answer 2

Use point-slope form.

The slope of the perpendicular is the negative reciprocal of -1, That number is 1.

(y +4) = 1(x + 9)