Differentiate y=arccos(e4x).,,,, dy/dx = ?

Question

Differentiate y=arccos(e4x),,,, dy/dx = ?

Answer 1

I'm assuming that your equation is supposed to say: y = arccos(e^(4x) ).

One thing you might consider trying is to rearrange the equation into a form that looks slightly more formidable to differentiate since I sure don't know what the derivative of arccos is off the top of my head. Instead, we can rearrange the above equation as

cos(y) = e^(4x)

Now, using implicit differentiation, we can take d/dx on both sides and solve for dy/dx. Does that make sense?