Mathematic, statistics 150

Question

In the rolling of two fair dice calculate the following: 

P(Sum of the two dice is 4)=  .

P(Sum of the two dice is 6)=  .

P(Sum of the two dice is not 9)=  .

P(Sum of the two dice is 5 or 10)=  .

P(Sum of the two dice is not 7 and not 8)=  

Answer 1

When you roll two dice there are 6 * 6 = 36 possible outcomes.

You can make a table of sums of the two dice:

1 2 3 4 5 6

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

For each of the probabilities you determine how often the specified event occurs out of 36 possibilities.

For example: P(Sum of the two dice is 4).

From the table the event that the sum of the two die is 4 occurs 3 times, so the probability is 3/36 = 1/12.

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