F'(x) = (-3-x^2) / x^2 for x

Question

F'(x) = (-3-x^2) / x^2 for x <0. Find the x = c values for f(x) on the interval [-3,-1] guaranteed by the MVT given that f(-1) =-2 and f(-3)=2

Edward C. · Accepted Answer

Hi Danielle,

There are 2 steps to answering this question.

1.) Find the slope of the line connecting f(-3) and f(-1).

2.) Find the value of x in the interval (-3,-1) where f'(x) is equal to the slope found in step 1.

Which part do you need help with?

F'(x) = (-3-x^2) / x^2 for x <0. Find the x = c values for f(x) on the interval [-3,-1] guaranteed by the MVT given that f(-1) =-2 and f(-3)=2