L'Hopital's rule
since the limit as-is approaches 0/0, you can take the derivative of top and bottom and try again
lim θ->0 of 5/(1/(θ+1)) = (5θ+5)/1
Now when you plug in 0, you don't get 0/0, you get 5/1 = 5
Giselle H.
asked 04/01/20Evaluate the limit: lim theta approaches 0 tan(5theta)/ln(theta+1)
L'Hopital's rule
since the limit as-is approaches 0/0, you can take the derivative of top and bottom and try again
lim θ->0 of 5/(1/(θ+1)) = (5θ+5)/1
Now when you plug in 0, you don't get 0/0, you get 5/1 = 5
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