Michael H. answered 03/29/20
High School Math, Physics, Computer Science & SAT/GRE/AP/PRAXIS Prep
Since 5i is a root and all the coefficients are real, then -5i must also be a root.
Since both 5i and -5i are roots, then P(x) must be divisible by both (x - 5i) and (x + 5i), and so it must be divisible by the product: (x - 5i) (x + 5i) = (x2 + 25).
Also, one should always check for roots at 1 and -1, where we find that P(-1) = 0, and so (x+1) is also a factor.
Dividing out (x2 + 5) and (x + 1) leaves us with the quadratic: 3x2 - 4x - 15, whose roots are easily found to be 3 and -5/3, and so the quadratic can be factored as (x - 3) (3x + 5)
Hence, in factored form, P(x) = (x - 5i) (x + 5i) (x + 1) (x - 3) (3x + 5)