systems of linear equations

Question

Two pools are being filled with water. To start, the first pool contains 1900

 liters of water and the second pool contains 1645

liters of water. Water is being added to the first pool at a rate of 25.25

 liters per minute. Water is being added to the second pool at a rate of 32.75

 liters per minute. 

After how many minutes will the two pools have the same amount of water?

___minutes

How much water will be in each pool when they have the same amount?

___liters

Answer 1

Let,

x = number of minutes that elapsed

the 1st pool contain 1900 liter of water

so after x minute

25.25* x + 1900

the second pool contain 1645 liter of water

so after x minute

32.75*x + 1645

Amount of water of pool 1 after x minute = Amount of water of pool 2 after x minute

25.25 * x + 1900 = 32.75 * x + 1645

1900-1645 = 32.75x -25.25x

255 = 7.5x

x = 34

The first pool will have a total of 25.25 * x +1900

25.25 * 34 +1900 =2758.5 liter

The second pool will have a total of 32.75 * x +1645

32.75 * 34 +1645 = 2758.5 liter

After how many minutes will the two pools have the same amount of water?

34 minutes

How much water will be in each pool when they have the same amount?

2758.5 liters