V(cube) = x3
dV/dt = 63/3 = 72 inches2/min = 3x2 (dx/dt)
dx/dt = 72/(3*62) = 2/3 inch/min
V(room) = l * w * h
dV/dt = l * w * (dh/dt) + (dl/dt) * w * h + l * (dw/dt) * h
dl/dt = dw/dt = 2/3 inch/min
72 = (10)(12)(dh/dt) + (2/3)(12)(5) + (10)(2/3)(5)
dh/dt = ?
The given information is not cleared if the room and the box are the same or if the water flow is flowing at the same rate. This is the solution I can figure out, let me know if you have any doubts and if this does not make sense. Thanks.