There may be an easier way to do this, but this way will work.
You need to break up the area into 4 parts.
Part 1: the integral from 0 to 5 sqrt(2x-2)
Part 2: the integral from 5 to 9 sqrt(2x-2)-(x-5)
Part 3: the integral from 0 to 3 of sqrt(2x-2)...this will be a positive area number which is actually the correct value for the area between -sqrt(2x-2) and the x-axis.
Part 4: the integral from 3 to 5 of x-5...but change the sign of the answer to positive.
Then add all the parts together.

Paul M.
03/24/20
Ainedra H.
I don't understand at all 😥03/24/20