Denise G. answered 03/19/20
Algebra, College Algebra, Prealgebra, Precalculus, GED, ASVAB Tutor
Let x = width
Let y= length
Area = xy
Perimeter = x+x+y Plug in known values
192=xy
40=2x+y
This is 2 equations, 2 unknowns. It can be solved by substitution, as one possibility.
Solve for y in the second equation
y=40-2x Plug this into the area equation
192=x(40-2x) Distribute
192 = x(40-2x) Distribute
192 = 40x-2x2 Add 2x2 and subtract 40x from both sides
2x2-40x+192 = 0 Divide both sides by 2 to simplify
x2-20x+96 = 0 Factor
(x-12)(x-8)=0 Set equations equal to zero and solve
x=12 or x=8
Now find y for these solutions.
y=192/12
y=16
x=12
12+12+16=40
y=192/8
y=24
x=8
8+8+24 = 40