A 1,250 kg Toyota Supra makes a right turn on a race track that has a radius of 10 meters. What is the coefficient of friction for the surface if the car makes the turn at a constant speed of 5 m/s?

Question

A.0.66

B.0.25

C.0.33

D.0.15

Answer 1

Get the coefficient of friction by equating the static force of friction to the centripetal force.

μmg = mv²/r

μ = v² / (rg) = (5 m/s)² / [(10 m)(9.8 m/s²)] = 0.255

Note μ has no units.