Probability Question

Question

Out of 8 bars in a town which offer to pay bands to perform, one is run by a sleazy operator who does not pay bands after they play, while the other seven bars pay the promised amount.  What is the probability that the band plays two gigs at this town, 3 weeks apart, and does not get paid either time?  Assume the band is offered a gig at a random location each time.

Answer 1

The probability that they don't get paid at the first gig is 1/8.  The probability that they don't get paid at the second gig is also 1/8.  These two are independent random events.  So the probability that they don't get paid both times is the product of these two = 1/64.