Matthew S. answered 03/09/20
PhD in Mathematics with extensive experience teaching Calculus
1) The integrand is [(2x - 3)2]^(5/2) = (2x - 3)5 (i.e., the exponents 2 and 5/2 multiply)
After factoring the integrand, I'll multiply and divide by 2 as follows:
∫(2x - 3)5dx = 1/2 * ∫(2x - 3)52dx. Since 2dx is d/dx of the parenthesized expression, this is equal to
1/2 * 1/6 * (2x - 3)6 + C, or (2x - 3)6/12 + C
2) Set u = √x. Then du = 1/(2√x) * dx
The integral becomes 1/2 * ∫csc2(u)du = -1/2 * cotan(u) + C = -1/2 * cotan(√x) + C