Sam Z. answered • 03/06/20
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All you've got to do is place a value for "x". Make a table "x", "y".
Lola P.
asked • 03/06/20Solve each system of equations algebraically
y = 1/2x^2 - 4x + 12
y = -2x^2 - 12x - 23
2x^2 + 12x - y = -17
y = -x^2 - x + 7
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Lola P.
sorry but this is not the answer i was looking for i needed to solve the systems03/07/20