Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the line y = 3.

Question

y=(1-x)...in square root

x=0

y=0

Answer 1

I'm uncertain what you mean by x=0, y=0.

I interpret this to be π∫((√(1-x))²dx from 0 to 1.

This equates to π√(1-x)dx = π(x -x²/2 ) from 0 to 1 = π/2