Given f(x) find f'(x)

Question

If f(x)= ∫(t^2-1)/(t^2+1) dt [8,x^3], Find f'(x).

Answer 1

Hi Ana,

f(x)= ∫(t^2-1)/(t^2+1) dt [8,x^3], Find f'(x).

f'(x) = 3x^2 * ( x^2 - 1) (x^2 +1)

in fact when F(x) = ∫ g(t) dt [a, h(x)]

derivative of F(x) = h'(x) * g(x)

(BE SURE a is a number)

I hope it is useful,

Minoo