Let x = 6 tan u, then x2 = 36 tan2u and dx = 6 sec2u du
The integrand becomes 36 tan2u times 6 sec2u du/36 sec4u
which becomes (1/6) sin2u du and the integral is (1/2)u - (1/4)sin 2u
which can be converted back to the variable x
Matt D.
asked 02/24/20intergral of x^2/(36+x^2)^2 dx
Let x = 6 tan u, then x2 = 36 tan2u and dx = 6 sec2u du
The integrand becomes 36 tan2u times 6 sec2u du/36 sec4u
which becomes (1/6) sin2u du and the integral is (1/2)u - (1/4)sin 2u
which can be converted back to the variable x
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