A plane flies 220 miles in an hour with the jet stream. The return flight against the jet stream to the the original hangar takes 2 hours.

Answer 1

distance = velocity x time

d=vt v1=d/t = 220/1= 220mph with the jet stream v2=220/2 =110 mph against the jet stream

Let the velocity of the plane with no jet stream = v. Let j= the velocity of the jet stream

v+j=v1=220

v-j=v2=110

v+j=220

v-j=110

add those two equations to get 2v=330 or v= 165 mph

v+j=220

165+j+220.

j=220-165=55 mph

j=55 mph

The velocity of the jet stream is 55 mph

The velocity of the plane alone is 165 mph

v1=165+55=220 mph plane's speed with the jet stream

v2=165-55=110 mph plane's speed =against the jet stream