
AC G.
asked 02/12/20Calculus: Vector Integration
Three paths from (0,0) to (1,2) are defined by
(a) y=2x
(b) y=2x^2
(c) y=0 from (0,0) to (1,0) and x= 1 from (1,0) to (1,2).
Sketch each path and along each path find (integral)c Fdr, where F= y^2i+xyj
1 Expert Answer

Yefim S. answered 02/18/20
Math Tutor with Experience
Fdr = (y2i + xyj)(dxi + dyj) = y2dx + xydy;
∫lFdr = ∫l(y2dx + xydy) where l is contur of integration.
a) l is line y = 2x, then dy = 2dx and 0≤x≤1; Then our integrl ∫lFdr = ∫01(4x2dx +4x2dx) = ∫018x2dx =8/3x301 = 8/3.
b) l is line y = 2x2, then dy = 4xdx and 0≤x≤1. Then our integral ∫lFdr = ∫01(4x4 + 8x4)dx = (12x5/5)01 = 12/5;
c) l is l1 y = 0 ,dy = 0, 0≤x≤1 and l2 x = 1, dx = 0 and 0≤y≤2.
Then ∫lFdr = ∫02ydy = y2/202 = 2
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Stanton D.
I THINK you want the equation F=(y^2).coordinate.(i) + (xy).coordinate.(j) ? Then, substitute each of the equalities respectively into that F equation, so that they're only f(x). That will let you express Fdr in terms of the i and j coefficients (geometry and Pythagoras!) as f(x) dx, and you can let x run as it will (i.e. integrate by dx instead). For path (c), instead express as f(y), since F has NO i component for the first part (y=0), but you DO have product Fdr for the upward leg, and x is constant (it appears in the Fdr equation, but as the value 1). --Cheers, -- Mr. d.02/13/20