Matthew C. answered 01/29/15
Tutor
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Math, Science, and SAT Tutoring from a Carnegie Mellon Math Major
This one isn't too bad so I'll be leaving a lot of the legwork to you.
The first thing you probably want to do is convert your equation into y=mx+b form. This gives:
y=(9x-4)/7=(9/7)x - 4/7
From this you should be able to figure out the slope. (Hint: it's "m")
Now the thing that makes lines parallel is the slope. Now that we've extracted that we can move onto the next step.
The easiest way to write the equation for a line that passes through a point is called "point-slope form" and it looks like this:
y-y0=m(x-x0) where x0 and y0 are the coordinates of your point.
You can test the accuracy of this by plugging one of your coordinate values into the equation to get the other coordinate value. This shows that the line contains the point specified.
Then you do some easy algebra to turn it into y=mx+b form and you're done. We know that it is parallel because it has the same slope (m) and that it goes through the point with the double check just above.
Good Luck!
Matthew C.
If you followed the instructions that I gave you should have an equation for the line in the form:
y-5 = (9/7)*(x+8)
This is, as stated above, point-slope form. From here we can do some algebra to manipulate it into the form y=mx+b. It isn't the prettiest solution, but it is the correct one.
y = (9/7)*(x+8) + 5
= (9/7)x + 72/7 + 5
= (9/7)x + 107/7
This is the equation in mx+b form where:
m=9/7
b=107/7
The y intercept occurs when x=0. Plugging that in we get:
y = (9/7)(0) + 107/7
= 107/7
So the y-intercept is 107/7
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01/29/15
Kelvin T.
01/29/15