Arthur D. answered 01/28/20
Mathematics Tutor With a Master's Degree In Mathematics
distance=(# of gallons used)*(miles/gallon)
let g=# of gallons in the tank when full
25=(g-14)(m/g) m=# of miles g=# of gallons
65=(g-10.8)(m/g)
25g=(g-14)m
25g/(g-14)=m
65g=(g-10.8)m
65g/(g-10.8)=m
notice there are two equations equal to "m"
set them equal to each other
25g/(g-14)=65g/(g-10.8)
cross multiply
25g(g-10.8)=65g(g-14)
25g^2-270g=65g^2-910g
65g^2-25g^2-910g+270g=0
40g^2-640g=0
divide by 40
g^2-16g=0
factor
g(g-16)=0
g-16=0
g=16
the tank holds 16 gallons of gas
from the information given...
you travel 25 miles on 2 gallons of gas and travel 65 miles on 5.2 gallons of gas
25/2=12.5 miles per gallon and 65/5.2=12.5 miles per gallon also
miles driven(m)=gallons used(16-g) * 12.5mpg
so, m=(16-g)*12.5
you want m to be the independent variable
m/12.5=16-g
g=16-(m/12.5) (answer)
plug in 25 for m and plug in 65 for m to see that this is correct-that you get the amount of gas left in the tank
the domain of m is 0≤m≤200
the range is 0≤g≤16