Katie S.

asked • 01/28/20

Find two positive numbers satisfying the given requirements. The product is 192 and the sum is a minimum.

1 Expert Answer

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Anita A. answered • 01/28/20

Tutor
4.9 (231)

Community College Math Instr; TX Secondary Mathematics Certification

Katie S.

hi, nope I wrote the exact problem from the book.
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01/28/20

Anita A.

Hi Katie, Assuming that the 2 positive numbers don't have to be rational numbers, this can be solved. We know that xy =192. Solving that for y, we get y = (192/x). Then the sum x + y can be represented by x + (192/x). Let f(x) = x + (192/x) = x + 192x^(-1) f'(x) = 1 - 192x^(-2) Set f'(x) = 0 0 = 1 - 192x^(-2) or 192x^(-2) = 1 (192/x^(-2)) =1 192 = x^2. Since we are concerned with positive numbers, x = √(192) x = 8√(3) Then y = (192/x) = (192/x) The minimum sum then for x + y = 16√(3). Regards, Anita A.
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02/01/20

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