f'(x) = 2 - 2 cos 2x
f'(x) = 0 where cos 2x = 1 which means 2x = 0 or 2π, i.e. x = 0 or x = π
Find the x-coordinates where f '(x) = 0 for f(x) = 2x – sin(2x) in the interval [0, 2π].
Thank you so much in advance!
f'(x) = 2 - 2 cos 2x
f'(x) = 0 where cos 2x = 1 which means 2x = 0 or 2π, i.e. x = 0 or x = π
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Ana C.
Thank you so so much!! You're the best! :)01/16/20