Mark H. answered • 01/10/20
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position: s(t) = 4sin(t) - cos(2t)
acceleration of the particle at time t = 0 seconds.
velocity is the 1st derivative of distance, and acceleration is the second derivative, SO:
v(t) = s'(t) = 4cos(t) - (-sin(2t) * 2) =4cos(t) +2sin(2t)
v(t) =4cos(t) +2sin(2t)
a(t) = v'(t) = -4sin(t) + 4cos(2t)
Plug in t = 0 to get the final answer
Mark H.
sin(0) = 0, and cos(0) = 1, so the correct answer is indeed 4. Acceleration is ft/sec^2, which can be read as "feet per second per second". Note the ambiguity if t is not 0: we don't know whether the trig functions use degrees or radians. (not an issue in this case)
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01/10/20
James Nicholas F.
I have reached an answer of 4. Is this correct? Assuming this is correct, would I write my final answer as 4 ft/sec?01/10/20