Help with Calculus!!

Question

A particle moves with velocity function v(t) = 3t² - 4t + 1, with v measured in feet per second and t measured in seconds. Find the acceleration of the particle at time t = 3 seconds.

Question options:

1)	feet per second2
2)	7 feet per second2
3)	14 feet per second2
4)	21 feet per second2

Answer 1

v(t) = 3t² - 4t + 1

acceleration is the 1st derivative of velocity, so:

a(t) = v'(t) = 6t - 4

a(3) = 14