Patrick B. answered 01/03/20
Tutor
4.7
(31)
Math and computer tutor/teacher
y = sec(x^2)
y' = sec(X^2) tan(x^2) (2x)
option #1
Nick F.
asked 01/03/20Question 4 options:
| 1) | 2xsec(x2)tan(x2) |
| 2) | ![]() |
| 3) | ![]() |
| 4) | ![]() |
Patrick B. answered 01/03/20
Math and computer tutor/teacher
y = sec(x^2)
y' = sec(X^2) tan(x^2) (2x)
option #1
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