
Patrick B. answered 01/01/20
Math and computer tutor/teacher
False
Here is a counter example
y = f(x) = |x| = sqrt(x^2) = (x^2)^(1/2)
y' = (1/2)(x^2)^(-1/2) ( 2x) = -x/x^2 = -1/x
the derivative does not exist at x=0
therefore the function is not differentiable at x=0
Continuity does NOT guarantee differentiability..
However, differentiability does guarantee continuity