
Mark H. answered 01/01/20
Tutoring in Math and Science at all levels
f(x) = x3 - 3x2 - 9x + 2
To find the maxima and minima, take the 1st derivative and set = to 0:
f'(x) = 3x2 - 6x - 9 = 0
x2 - 2x - 3 = 0
x = 2, -1
Only x = 2 falls in the specified interval. Solve f(x) for x = 2:
8 - 12 - 18 + 2 = -20 This appears to be a local minimum. It appears that the maximum will be at x = 6:
f(6) = 216 - 108 - 54 + 2 = 56
CHECK by graphing the function using a graphing calculator or online tool.