a fish has a head 6 inches long and its tail was as long as its head and half of its body and its body was half of its whole length. How long was the fish

Question

I really need help I don't get it

Answer 1

Let x = length of fish

 

Then, ½x = length of body

            6 + (½)(½x) = 6 + ¼x = length of tail

 

Length of fish = length of head + length of body + length of tail

 

x = 6 + ½x + 6 + ¼x

 

x = 12 + ¾x

 

¼x = 12

 

x= 48"

 

ANSWER:  The length of the fish is 48".

Answer 2

x=length of the fish

6=length of the head in inches

x/2=length of the body

6+(1/2)(x/2)=6+(x/4)=length of the tail

the length of the fish is the length of the head+the length of the body+the length of the tail

x=6+(x/2)+(6+[x/4])

x=6+(x/2)+6+(x/4)

x=12+(x/2)+(x/4) where x/2=2x/4

x=12+(2x/4)+(x/4)

x=12+(3x/4)

x-(3x/4)=12

(1/4)(x)=12

multiply both sides by 4

(4)(1/4)(x)=4(12)

x=48 inches is the length of the fish

head=6 inches

body=24 inches

tail=12+6=18 inches