What is the approximate probability of Peter drawing out two green marbles?

Question

Peter has a bag of marbles. In the bag are 4 white marbles, 2 blue marbles, and 6 green marbles. Peter randomly draws one marble, sets it aside, and then randomly draws another marble. What is the approximate probability of Peter drawing out two green marbles?

Answer 1

p(A and B) = p(A) x p(B)

First draw there are 6 green and 12 marbles total. P(green) = 6/12 =1/2 for this event.

If he sets it aside, there are 5 green left and 11 total P(second green) = 5/11

p(A and B) = (1/2)(5/11) = 5/22