What the probability that the team will win the second game given that they have already won the first game?

Question

The baseball team has a double -header on Saturday. The probability that they will win both games is 42% . The probability that they will win the first game is 60%. What the probability that the team will win the second game given that they have already won the first game?

Answer 1

This problem fits the conditional probability formula very well. The formula is P(B|A) = P(B ∩ A)/P(A). If event A is winning the first game, and event B is winning the second, then P(B ∩ A) = 0.44, and P(A) = 0.6. So P(B|A) is obtained by dividing 0.44 by 0.6, which is about 0.733.