Find the average value of f(x)=x^3 on [-1,1]
I understand that this is the formula 1/(b-a)∫ f(x) dx but im having trouble plugging in the values correctly. Any light on the subject would be much appreciated!
2 Answers By Expert Tutors
Average value = (1 / [1-(-1)]) ∫(-1 to 1) x3dx
= (1/2)[(1/4)x4(from -1 to 1)
= (1/8)[(1)4 - (-1)4] = 0
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