Find the average value of f(x)=x^3 on [-1,1]

Question

I understand that this is the formula 1/(b-a)∫ f(x) dx but im having trouble plugging in the values correctly. Any light on the subject would be much appreciated!

Answer 1

Average value = (1 / [1-(-1)]) ∫_{(-1 to 1)} x³dx

= (1/2)[(1/4)x⁴_{(from -1 to 1)}

= (1/8)[(1)⁴ - (-1)⁴] = 0

Answer 2

Graph x³.

From the graph you should see the answer immediately.