No, it's not. Linear transformations require, among other things, that the zero vector in the domain maps to the zero vector in the codomain. The given transformation maps (0,0,0) to (0,-5).
Raven F.
asked • 12/04/19Help with linear algebra
is the function below a linear transformation? why or why not?
T:C3 ---> C2, T([x1][x2][x3]) = [-1x1-7x2+3x3],[-1x1+8x3-5]
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