Graph both equations.
Graphically it appears that the point on the curve you are looking for is (3,3)
And if you differentiate implicitly you will find that the derivative of the curve is, in fact, -1 at (3,3)
The equation of the tangent line is -1=(y-3)/(x-3)
It also appears graphically (but I'm not sure analytically) that the slope of the curve approaches -1 when x
goes to either + or - infinity.
12/4/2019 2 PM
No! The tangent is a straight line with a linear equation. The equation I have given is correct. What you have written is dy/dx = -1, i.e. you have derived the derivative correctly and set it = to -1 as needed.
