Arturo O. answered • 12/03/19
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m = kxy
k = constant
10 = k(2)(14) = 28k
k = 5/14
For x = 11 and y = 8,
m = kxy = (5/14)(11)(8) = ?
Prithvi S.
asked • 12/03/19Proportional Problems
If M varies jointly as x and y, and m=10 when x=2 and y=14, find m when x=11 and y=8
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