Arturo O. answered • 12/03/19

Experienced Physics Teacher for Physics Tutoring

m = kxy

k = constant

10 = k(2)(14) = 28k

k = 5/14

For x = 11 and y = 8,

m = kxy = (5/14)(11)(8) = ?

Prithvi S.

asked • 12/03/19If M varies jointly as x and y, and m=10 when x=2 and y=14, find m when x=11 and y=8

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Arturo O. answered • 12/03/19

Experienced Physics Teacher for Physics Tutoring

m = kxy

k = constant

10 = k(2)(14) = 28k

k = 5/14

For x = 11 and y = 8,

m = kxy = (5/14)(11)(8) = ?

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