
William W. answered 12/03/19
Experienced Tutor and Retired Engineer
Newtons Method finds zeros. To find the intersection of f(x) and g(x), we can just equate the two functions. So letting f(x) = g(x), we can say 2x + 2 = √x + 6.
To find the zeros of a function, I set the function equal to zero. So let's take 2x + 2 = √x + 6 and subtract √x from both sides and subtract 6 from both sides to get 2x + 2 - √x - 6 = 0 or 2x - √x - 4 = 0. We can now say:
h(x) = 2x - √x - 4
Taking the derivative, we can say
h'(x) = 2 - 1/2x-1/2
Let's let x1 = 1 (just arbitrarily)
Then x2 = x1 - h(x1)/h'(x1) = 1 - -3/1.5 = 1 - -2 = 3
So x2 = 3
Then x3 = x2 - h(x2)/h'(x2) = 3 - 0.2679491924/1.711324865 = 3 - .1565741245 = 2.843425876
So x3 = 2.843425876
Then x4 = x3 - h(x3)/h'(x3) = 2.843425876 - 6.056620119x10-4/1.703483375 = 2.843425876 - 3.555432479x10-4 = 2.843070333
So x4 = 2.843070333
This differs from x3 by < 0.001 so we have a solution per the instructions. The intersection point occurs at x = 2.843
To find the y value, we can just find f(2.843070333) which is 7.686 so the intersection point is (2.843, 7.686)