Let V=62500
V=hs2 where h is height and s is side of square
h = V/s2
The amount of material needed is 4hs + s2 = 4V/s + s2
The derivative of the amount of material is -4V/s2 +2s and is 0 when s = (2V)1/3
You can do the actual calculation!
Hammad S.
asked 12/01/19You are the manager of a delivery company and you want wooden crates with an open top and a square base. The volume of each crate needs to be exactly 62500cm3 and as the manager you want the cost of material to be minimized as well. Find the demensions of the crate to minimize the amount of material.
Let V=62500
V=hs2 where h is height and s is side of square
h = V/s2
The amount of material needed is 4hs + s2 = 4V/s + s2
The derivative of the amount of material is -4V/s2 +2s and is 0 when s = (2V)1/3
You can do the actual calculation!
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