Patrick B. answered 12/01/19
Math and computer tutor/teacher
x = 5*sin t ; then dx = 5* cos T dT --> (1/5) dx = cos T dT
f(5 * sin t) * cos(t) dt = (1/5) * f(x) * dx
when x=0, 0 = 5 * sin t ---> 0 = sin t ---> t = 0
when x=5, 5 = 5 * sin t --> 1 = sin t ---> t = pi/2
Therefore, integral f(5 * sint)* cost dt , t = 0...pi/2 =
1/5 * integral f(x) dx, t = 0...5
= 12/5