Arman G. answered 11/21/19
Aerospace Engineer
L = 29 = x+2h+πr (πr is half the circumference of a circle)... 2r = x according to the problem so
29 = x +2h +πx/2 , so h = (29 - x - πx/2)/2 and plug that into area
Area = xh + .5*pi*r2 = xh + πx2/4... plug in h term and it's now just a function of x, take the derivative and set it equal to zero, get the x value, plug it into Area function (not the derivative of area, but the Area itself)